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6x^2-1.8x=0
a = 6; b = -1.8; c = 0;
Δ = b2-4ac
Δ = -1.82-4·6·0
Δ = 3.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.8)-\sqrt{3.24}}{2*6}=\frac{1.8-\sqrt{3.24}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.8)+\sqrt{3.24}}{2*6}=\frac{1.8+\sqrt{3.24}}{12} $
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